63x^2-320x+384=0

Solution for 63x^2-320x+384=0 equation:

63x^2-320x+384=0

a = 63; b = -320; c = +384;
Δ = b2-4ac
Δ = -3202-4·63·384
Δ = 5632
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5632}=\sqrt{256*22}=\sqrt{256}*\sqrt{22}=16\sqrt{22}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-320)-16\sqrt{22}}{2*63}=\frac{320-16\sqrt{22}}{126}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-320)+16\sqrt{22}}{2*63}=\frac{320+16\sqrt{22}}{126}
$